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root 5 is an irrational number . prove that |
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Answer» I know "√5 is an “irrational number”.Given:√5To prove:√5 is a rational numberSolution:Let us consider that √5 is a “rational number”.We were told that the rational numbers will be in the “form” of\xa0form Where “p, q” are integers.So,\xa0we know that \'p\' is a “rational number”. So 5 \\times q should be normal as it is equal to pBut it did not happens with √5 because it is “not an integer”Therefore, p ≠ √5qThis denies that √5 is an “irrational number”So, our consideration is false and √5 is an “irrational number”." Book mai hai bhai |
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