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Root 2 by root 6 -root 2 -root 3 by root 6 +root 2 |
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Answer» {√2/(√6-√2)} - {√3/(√6+√2)} = [{√2(√6+√2)}-{√3(√6-√2)}]/(6-2) = [√12+2-√18+√6]/4 = (√12)/4 + 2/4 - (√18)/4 + (√6)/4 = √3/2 + 1/2 - (3/2√2) + √6/4 Hope it's HELPFUL to you. |
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