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(रिस्द, पेहा, n=a &Hro a-olgze ही. - y :bw[—eve.. 5 4 Uoen Presन (0दी |
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Answer» x = a sin theta : y = b tan theta ....(Given)L.H.S. = a²/x² - b²/y² = a²/(a sin theta)² - b²/(b tan theta)²a² and b² are cancelled and then we get1/sin² theta - 1/sin² theta/cos² theta ...[∴ tan theta = sin theta/cos theta]1/sin² theta - cos² theta/sin² theta= (1-cos² theta)/sin² theta ....[∴ sin² theta + cos² theta = 1]sin² theta/sin² theta = 1= R.H.S⇒ a²/x² - b²/y²Hence proved. Like my answer if you find it useful! |
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