Saved Bookmarks
| 1. |
Resolve into factors :--a(a-1) x² + (2a²-1)x + a(a+1) |
|
Answer» Answer: Step-by-step explanation: Given----> a ( a - 1 )x² + ( 2a² - 1 ) x + a ( a + 1 ) To find----> Resolve in to FACTORS Solution----> ATQ, a ( a - 1 )x² + ( 2a² - 1 )x + a ( a +1 ) We break , 2a² - 1 = ( a² + a² ) - 1 Rearranging terms , we get, = ( a² - 1 ) + a² = { ( a )² - ( 1 )² } + a² Applying a² - b² = ( a + b ) ( a - b ) , we get , = ( a + 1 ) ( a - 1 ) + a² Now returning to original problem a( a - 1 )x² + ( 2a² - 1 ) x + a ( a + 1 ) Now putting VALUE of ( 2a² - 1 ) , we get, a( a - 1 )x² + { ( a + 1 ) ( a - 1 ) + a² } x + a ( a + 1 ) Multiplying by x in middle term , we get, => a ( a - 1 )x² + ( a + 1 ) ( a - 1 ) x + a²x + a ( a + 1 ) Taking ( a - 1 )x , Common from first TWO terms and taking a , common from last two terms => ( a - 1 )x { ax + ( a + 1 ) } + a { ax + ( a + 1 ) } Taking { ax + ( a + 1 ) } common , we get, => { ax + ( a + 1 ) } { ( a - 1 )x + a } => ( ax + a + 1 ) ( ax - x + a ) |
|