Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.

Resolve a weight of 10 N in a direction parallel to a slope inclined a

1.	Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.
Answer» ᴛᴇ ! ⭐ᴀɴsᴡᴇʀ⭐Let the force 10N makes an ANGLE θ with the INCLINED lineparallel component = 10×sinθ N ; PERPENDICULAR component = 10×cosθ N

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Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.​

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Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.