1.

Resolve 2x+3/5(x+2)(2x+1) into partial fractions.​

Answer»

Step-by-step EXPLANATION:

Let I=

X

2

+2x−3

2x

2

+5x−11

=

x

2

+2x−3

2(x

2

+2x−3)+x−5

=2+

x

2

+2x−3

x−5

=2+

(x+3)(x−1)

x−5

Now

(x+3)(x−1)

x−5

=

(x−1)

A

+

(x+3)

B

⇒x−5=A(x+3)+B(x−1)

On COMPARING coefficients we get

1=A+B,−5=3A−B

⇒A=−1,B=2

Therefore

I=2−

x−1

1

+

x+3

2

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