1.

resistance of motor is 200 ohms and the current maximum is 2.2Amps.find the main voltage supply so it works efficiently​

Answer»

ANSWER :

  • Voltage of the motor of resistance 200 Ω and with a current of 2.2 A is 440 V.

Explanation :

Given :

  • Resistance in the motor, R = 200 Ω
  • Current in the motor, I = 2.2 A

To find :

  • Voltage in the circuit, V = ?

KNOWLEDGE required :

  • The equation for Ohm's law :

⠀⠀⠀⠀⠀⠀⠀⠀⠀V = IR

Where,

  • V = Voltage in the circuit.
  • I = Current in the circuit.
  • R = Resistance in the circuit.

Solution :

By using the first equation of motion and substituting the values in it, we get :

⠀⠀=> V = IR

⠀⠀=> V = 2.2 × 200

⠀⠀=> V = 22/10 × 200

⠀⠀=> V = 22 × 20

⠀⠀=> V = 440

Therefore,

  • Voltage in the circuit, V = 440 V


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