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Represent the zeroes of the quadratic polynomial x^2-6x+9 graphically |
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Answer» SOLUTION Let y = f(x) or, y=x 2 −6x+9. The FOLLOWING table gives the values of y or f (x) for various values of x. x -2 -1 0 1 2 3 4 5 6 7 8 y=x 2 −6x+9 25 16 9 4 1 0 1 4 9 16 25 Thus, the graph of y=x 2 −6x+9 passes through the points (-2,25), (-1,16), (0,9), (1,4), (2,1),(3,0),(4,1),(5,4),(6,9),(7,16)and (8,25).Let us plot these points on the graph and draw a free HAND smooth curve passing through these points. We observe that the vertex of the parabola is at point P (3,0) as SHOWN in Figure. hope this helps you...plzz Mark as BRAINLIEST answer |
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