Between 81 and 237; 237 is greater than 81Division lemma of 237 and 81:Step 1:237 = 81 × 2 + 75Step 2:Since remainder 75 ≠ 0, division lemma is applied to 81 and 75 to get 81 = 75 × 1 + 6 Step 3:Since remainder 6 ≠ 0, division lemma is applied to 75 and 6 to get 75 = 6 × 12 + 3 Step 4:Since remainder 3 ≠ 0, division lemma is applied to 6 and 3 to get 6 = 3 × 2 + 0 The remainder is zero in step 4.Therefore, the divisor i.e. 3 in this step is the H.C.F. of the given numbers.The H.C.F. of 237 and 81 is 3Step 5:FromStep 3: 3 = 75 – 6 × 12 -----FromStep 2: 6 = 81 – 75 × 1Thus, fromStep 5, we, get 3 = 75 – (81 – 75 × 1) × 12⇒ 3 = 75 – (81× 12 – 75 × 12)Step 6⇒ 3 = 75 × 13 – 81× 12 FromStep 1, 75 = 237 – 81 × 2Thus, fromStep 6;3 = (237 – 81 × 2) × 13 – 81× 12⇒ 3 = (237 × 13 – 81 × 26) – 81× 12⇒ 3 = 237 × 13 – 81 × 38⇒H.C.F. of 237 and 81 = 237 × 13 + 81 × (–38)237 × 13 + 81 × (–38)is the representation of H.C.F. of 237 and 81 as linear combination of 237 and 81.