Remote Sensing satellite of Earth revolves in a circular orbit at a he

1.	Remote Sensing satellite of Earth revolves in a circular orbit at a height of 0.25×10^6 m above the surface of the Earth.If earth radius is 6.38×10^6 m and g=9.8 ms -2 then the orbital speed of the satellite is?
Answer» ➩Given:- •Height of a satellite h = 0.25 × 10^6m • Earth's radius, Re = 6.38 × 10^6m ➩Solution:- ➞For the satellite revolving AROUND the Earth, orbital velocity of the satellite vo = √GMe/Re = √GMe/ [ Re (1+ h/Re)] vo = √gRe/1+(h/Re) ➞Substitutes the VALUES of g, Re and h, we get vo = √60×10^6 m/s vo = 7.76 × 10^3m/s vo = 7.76 km/s ∴ The orbital SPEED of the satellite is 7.76 km/s!

Remote Sensing satellite of Earth revolves in a circular orbit at a height of 0.25×10^6 m above the surface of the Earth.If earth radius is 6.38×10^6 m and g=9.8 ms -2 then the orbital speed of the satellite is?

Answer»

➩Given:-

•Height of a satellite h = 0.25 × 10^6m

• Earth's radius, Re = 6.38 × 10^6m

➩Solution:-

➞For the satellite revolving AROUND the Earth, orbital velocity of the satellite

vo = √GMe/Re = √GMe/ [ Re (1+ h/Re)]

vo = √gRe/1+(h/Re)

➞Substitutes the VALUES of g, Re and h, we get

vo = √60×10^6 m/s

vo = 7.76 × 10^3m/s

vo = 7.76 km/s

∴ The orbital SPEED of the satellite is 7.76 km/s!

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Remote Sensing satellite of Earth revolves in a circular orbit at a height of 0.25×10^6 m above the surface of the Earth.If earth radius is 6.38×10^6 m and g=9.8 ms -2 then the orbital speed of the satellite is?​