1.

Remainder of x3-ax2+6x-a if divided by x-a

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Answer:

Here, p(X)=x 3+ax 2+6x−a, and the zero of x−a is a

So, p(a)=a 3+a×a 2+6×a−a =2A 3+5a

So, by the Remainder THEOREM, 2a 3+5a is the remainder when x 3+ax 2+6x−a is DIVIDED by x−a.


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