1.

Relative permeability of medium of refractive index 1.5 and dielectric constant 2 is ……. TmA^(-1). (mu_(0)=4pi xx10^(-7)TmA^(-1))

Answer»

(A) `0.45pi xx10^(-7)`
(B)`5pi XX 10^(-7)`
(C) `5pi xx 10^(-7)`
(D) `4.5pi xx10^(-7)`

Solution :`n=sqrt(mu_(r )K)rArr 1.5 = sqrt((mu_(r )K)`
`therefore (2.25)/(K)=mu_(r )=(mu)/(mu_(0))`
`therefore (mu)/(mu_(0))=(2.25)/(K)`
`rArr mu=(2.25xx4pi xx 10^(-7))/(2)`
`therefore mu=4.5 pi xx 10^(-7)TMA^(-1)`


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