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relationship between LIU UI(i) f(x) = x2 - 2x - 8 [NCERT] |
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Answer» Since an x² is produced, we know that the factorised version will be (x+a)(x+b). To find a and bwe need to consider the relationship between 2 and -8. It is going to be factorised into two brackets, due to the x², so we need to break the 2 down into 2 numbers that will add to give 2 and multiply together to give -8. The 8 is negative so one of these numbers must also be negative. These 2 numbers must be 4 and -2. Then substitude these numbers in to be a and b so the equation factorised is (x+4)(x-2) |
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