LET's the number of 1 rupee coins be x.

And the number of 5 rupee coins be y.

And the number of 1 rupee coins and 5 rupee coins combine together to get 200 coins.

So, let's write the above SITUATION arithmetically, or put it in an equation;

x + y = 200

And let's term the above equation as Equation 1.

And we can have one more equation, i.e., x + 5y = 320;

**How?? As we know that the total AMOUNT is ₹320, so the number of 1 rupee coins and the number of 5 rupee coins together is ₹320**

**Why 5y?? That's because y is just the number of coins, so we have to multiply 5 with it so that it becomes the amount of  5 rupee coins**

So, now let's term the above equation as Equation 2.

Now let's start solving the question;

First let's try to find the value of y using elimination;

So, by subtracting Equation 1 from Equation 2, we get;

4y = 120

As we have to isolate y, let's divide the equation by 4;

Simplify;

y = 30

Now, let's SUBSTITUTE the value of y to equation 1, to find the value of x;

x + (30) = 200

Subtract 30 from both the sides;

x + 30 - 30 = 200 - 30

Simplify;

x = 170

Therefore, there are 170 coins of 1 rupee and 30 coins of 5 rupee.