1.

Regular pentagon area,sides 38cm,76cm find

Answer» 1) SIDE(a)=38
AREA of a REGULAR pentagon=\frac{1}{4}  \sqrt{5(5+2 \sqrt{5} )}a ^{2}
if a side=38 ,,    area ≈2484.37 cm²

2)side(B)=76
area=\frac{1}{4}  \sqrt{5(5+2 \sqrt{5} )}a ^{2}
=9937.48 cm²


Discussion

No Comment Found

Related InterviewSolutions