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Referring to the previous illustration (a) Where do the particles meet? (b) What are the speeds of the particles at the time of meeting? |
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Answer» SOLUTION :(a)`s_(1)=(1//2)GT^(2)=(1//2)(10)(3)^(2)=45m`from the top (b)`v_(1)=gt_(1)=10xx3=30m//sec` `v_(2)=10-10xx(3-2)=0` |
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