Refer to the attachment ! please it's urgent

1.	Refer to the attachment ! please it's urgent
Answer» EXPLANATION: R= u²sin2x/g u²= GR/ sin2x mu²/2= mgR/ 2sin2x KE= mgR/2sin2x KEmax=> sin2x is to be min= - 1 KEmax= -mgR/2 here m and g have constant value therefore for Max KE RANGE should be half of it's max value. hence range = R/2 for Max K E this (c) is CORRECT.

Answer»

EXPLANATION:

R= u²sin2x/g

u²= GR/ sin2x

mu²/2= mgR/ 2sin2x

KE= mgR/2sin2x

KEmax=> sin2x is to be min= - 1

KEmax= -mgR/2

here m and g have constant value

therefore for Max KE RANGE should be half of it's max value.

hence range = R/2 for Max K E this (c) is CORRECT.

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Refer to the attachment ! please it's urgent ​

hence range = R/2 for Max K E this (c) is CORRECT.

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Refer to the attachment ! please it's urgent