Reenu got (2/7) part of an apple while sonal got (4/5) part of it. Who

1.	Reenu got (2/7) part of an apple while sonal got (4/5) part of it. Who got the larger part and by how much?
Answer» From the question, Reenu got (2/7) part of an apple Sonal got (4/5) part of an apple First we have to compare the given fraction (2/7) and (4/5) to know who got the larger part of the apple. Then, By cross multiplication, we have 2 × 5 = 10 and 4 × 7 = 28 But, 10 < 28 ∴ (2/7) < (4/5) So, Sonal got the larger part of the apple Now, = (4/5)-(2/7) = [(28-10)/35] = [18/35] ∴ Sonal got (18/35) part of the apple larger than Reenu.

Reenu got (2/7) part of an apple while sonal got (4/5) part of it. Who got the larger part and by how much?

Answer»

From the question,

Reenu got (2/7) part of an apple

Sonal got (4/5) part of an apple

First we have to compare the given fraction (2/7) and (4/5) to know who got the larger part of the apple.

Then,

By cross multiplication, we have

2 × 5 = 10 and 4 × 7 = 28

But,

10 < 28

∴ (2/7) < (4/5)

So, Sonal got the larger part of the apple

Now,

= (4/5)-(2/7)

= [(28-10)/35]

= [18/35]

∴ Sonal got (18/35) part of the apple larger than Reenu.