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Redox reactions play a pivotal role in chemistry and biology. The values standard redox potential `(E^(c-))` of two half cell reactions decided which way the reaction is expected to preceed. A simple example is a Daniell cell in which zinc goes into solution and copper sets deposited. Given below are a set of half cell reactions `(` acidic medium `)` along with their `E^(c-)(V` with respect to normal hydrogen electrode `)` values. Using this data, obtain correct explanations for Question. `I_(2)+2e^(-) rarr 2I^(c-)," "E^(c-)=0.54` `Cl_(2)+2e^(-) rarr 2Cl^(c-), " "E^(c-)=1.36` `Mn^(3+)+e^(-) rarr Mn^(2+), " "E^(c-)=1.50` `Fe^(3+)+e^(-) rarr Fe^(2+)," "E^(c-)=0.77` `O_(2)+4H^(o+)+4e^(-) rarr 2H_(2)O, " "E^(c-)=1.23` Among the following, identify the correct statement.A. Chloride ion is oxidized by `O_(2)`.B. `Fe^(2+)` is oxidized by iodine.C. Iodide ion is oxidized by chlorineD. `Mn^(2+)` is oxidized by chlorine. |
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Answer» Correct Answer - c `2I^(c-)+Cl_(2) rarr I_(2)+2Cl^(c-),E^(c-)._(cell)=1.36-0.54=0.82V` `E^(c-)._(cell)` is `+ve` . Thus, the cell reaction is feasible. |
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