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Real part of `(e^e)^(iotatheta)` is |
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Answer» `e^(e^(itheta)) = e^(cos theta + sin theta )= e^(cos theta)[e^(isin theta)]` `=e^(cos theta)[cos(sin theta) + i sin (sin theta)]` Therefore, the real part is `e^(cos theta) [cos (sin theta)]`. |
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