Rationalize the denominator of √3-√4/√3+√4-√7

1.	Rationalize the denominator of √3-√4/√3+√4-√7
Answer» Answer: $\frac{-1-\sqrt{21}+\sqrt{28} }{2\sqrt{12} }$ PLEASE MARK MY ASWER AS BRAINLIEST ! Step-by-step EXPLANATION: $\frac{\sqrt{3} -\sqrt{4} }{\sqrt{3}+\sqrt{4} - \sqrt{7} }$ $\frac{\sqrt{3} -\sqrt{4} }{\sqrt{3}+\sqrt{4} - \sqrt{7} }*\frac{\sqrt{3} +\sqrt{4}+\sqrt{7} }{\sqrt{3}+\sqrt{4} + \sqrt{7} }$ $\frac{(\sqrt{3} -\sqrt{4})(\sqrt{3}+\sqrt{4} - \sqrt{7}) }{(\sqrt{3}+\sqrt{4})^{2} - (\sqrt{7})^{2} }$ $\frac{3-\sqrt{12}+\sqrt{12}-4-\sqrt{21}+\sqrt{28} }{3+4+2\sqrt{3}.\sqrt{4} - 7 }$ $\frac{-1-\sqrt{21}+\sqrt{28} }{2\sqrt{12} }$

Answer»

Answer: $\frac{-1-\sqrt{21}+\sqrt{28} }{2\sqrt{12} }$