1.

Rationalize the denominator 1 / 3 + √3​

Answer»

Answer:

Step-by-step EXPLANATION:

\frac{1}{<klux>3</klux>+ \sqrt{3} } = \frac{1}{3+ \sqrt{3} } × \frac{3-\sqrt{3} }{3-\sqrt{3} }

\frac{3-\sqrt{3} }{3-\sqrt{3} } This basically means 1.

Now the NUMERATOR is 3 -\sqrt{3}.

Now you know that (a+B)(a-b) = a^{2} -b^{2}

So now put the value of 3 in a and \sqrt{3} in b.

So we get,

9 - \sqrt{3} × \sqrt{3}=

9 - 3 = 6

So we get,

\frac{3 -\sqrt{3}}{6}

So now the numerator is rationlised


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