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Rationalise the denominator of 3+52들5+2 |
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Answer» Step-by-step explanation: The given expression is \frac{3}{\sqrt{3}+\sqrt{5}-\sqrt{2}} 3
+ 5
− 2
3
RATIONALIZE the denominator. \frac{3}{(\sqrt{3}+\sqrt{5})-\sqrt{2}}\TIMES \frac{(\sqrt{3}+\sqrt{5})+\sqrt{2}}{(\sqrt{3}+\sqrt{5})+\sqrt{2}} ( 3
+ 5
)− 2
3
× ( 3
+ 5
)+ 2
( 3
+ 5
)+ 2
\frac{3(\sqrt{3}+\sqrt{5})+3\sqrt{2}}{(\sqrt{3}+\sqrt{5})^2-(\sqrt{2})^2} ( 3
+ 5
) 2 −( 2
) 2
3( 3
+ 5
)+3 2
\frac{3\sqrt{3}+3\sqrt{5}+3\sqrt{2}}{3+5+2\sqrt{15}-2} 3+5+2 15
−2 3 3
+3 5
+3 2
\frac{3\sqrt{3}+3\sqrt{5}+3\sqrt{2}}{6+2\sqrt{15}} 6+2 15
3 3
+3 5
+3 2
Rationalize the denominator. \frac{3(\sqrt{3}+\sqrt{5}+\sqrt{2})}{6+2\sqrt{15}}\times \frac{6-2\sqrt{15}}{6-2\sqrt{15}} 6+2 15
3( 3
+ 5
+ 2
)
× 6−2 15
6−2 15
\frac{3(\sqrt{3}+\sqrt{5}+\sqrt{2})(6-2\sqrt{15})}{6^2-(2\sqrt{15})^2} 6 2 −(2 15
) 2
3( 3
+ 5
+ 2
)(6−2 15
)
\frac{3(\sqrt{3}+\sqrt{5}+\sqrt{2})(6-2\sqrt{15})}{36-60} 36−60 3( 3
+ 5
+ 2
)(6−2 15
)
\frac{3(\sqrt{3}+\sqrt{5}+\sqrt{2})(6-2\sqrt{15})}{-24} −24 3( 3
+ 5
+ 2
)(6−2 15
)
-\frac{(\sqrt{3}+\sqrt{5}+\sqrt{2})(6-2\sqrt{15})}{8}− 8 ( 3
+ 5
+ 2
)(6−2 15
)
\frac{\sqrt{3}}{2}-\frac{3\sqrt{2}}{4}+\frac{\sqrt{30}}{4} 2 3
− 4 3 2
+ 4 30
Therefore the simplified form is \frac{\sqrt{3}}{2}-\frac{3\sqrt{2}}{4}+\frac{\sqrt{30}}{4} 2 3
− 4 3 2
+ 4 30
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