Rationalise the denominator of 1/ 7+4√3

1.	Rationalise the denominator of 1/ 7+4√3
Answer» $\frac{1}{(7+4\sqrt{3})}\\= \frac{(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})}\\ = \frac{(7-4\sqrt{3})}{7^{2}-(4\sqrt{3})^{2}}\\ = \frac{(7-4\sqrt{3})}{49- 48}\\ = 7 - 4\sqrt{3}$ THEREFORE., $\red{ \frac{1}{(7+4\sqrt{3})}}\green{ =7 - 4\sqrt{3}}$ •••♪

Answer»

$\frac{1}{(7+4\sqrt{3})}\\= \frac{(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})}\\ = \frac{(7-4\sqrt{3})}{7^{2}-(4\sqrt{3})^{2}}\\ = \frac{(7-4\sqrt{3})}{49- 48}\\ = 7 - 4\sqrt{3}$

THEREFORE.,

$\red{ \frac{1}{(7+4\sqrt{3})}}\green{ =7 - 4\sqrt{3}}$

•••♪

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Rationalise the denominator of 1/ 7+4√3

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