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Rationalise the denominator• 4/√2+√3• 2/√2-√5 |
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Answer» Answer: 1) 4/√2+√3. Rationalising DENOMINATOR of √2+√3 is √2-√3. Multiply NUMERATOR & denominator by √2-√3. 4/√2+√3×√2-√3/√2-√3. 4(√2-√3)/(√2)²-(√3)². (Because (a+b)×(a-b)=a²-b² where a=√2 & b=√3). 4√2-4√3/2-3. (Because √ & ² will cancel). 4√2-4√3/-1. (Because +×-=- & LARGEST number is important. -4√2-4√3. (Because +÷-=-). 2) 2/√2-√5. Rationalising denominator of √2-√5 is √2+√5. Multiply numerator & denominator by √2+√5. 2/√2-√5×√2+√5/√2+√5. 2(√2+√5)/(√2)²-(√5)². (Because (a+b)×(a-b)=a²-b² where a=√2 & b=√5). 2√2+2√5/2-5. (Because √ & ² will cancel). 2√2+2√5/-3. (Because +×-=- & largest number is important. -2√2+2√5/3. (Because +÷-=-). I think this is your answer. |
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