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Rationalise the denominator 3√5-√7÷3√3+√2 |
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Answer» Answer: [tex] \frac{3 \sqrt{5} - \sqrt{7} }{3 \sqrt{3} + \sqrt{2} } \\ = \frac{3 \sqrt{5} - \sqrt{7} }{3 \sqrt{3} + \sqrt{2} } \times \frac{{3 \sqrt{3} - \sqrt{2} }}{{3 \sqrt{3} - \sqrt{2} }} \\ = \frac{3 \sqrt{5}(3 \sqrt{3} - \sqrt{2} ) - \sqrt{7} (3 \sqrt{3} - \sqrt{2} )} { {(3 \sqrt{3}) }^{2} - { (\sqrt{2} )}^{2} } \\ = \frac{9 \sqrt{15} - 3 \sqrt{10} - 3 \sqrt{21} + \sqrt{14} }{27 - 2} \\ = \frac{9 \sqrt{15} - 3 \sqrt{10} - 3 \sqrt{21} + \sqrt{14} }{25} [tex]\ |
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