1.

Rationalise the denomination of [6-3√2/6+3√2]​

Answer»

Answer:

The rationalised value is

(6-3√2)/(6+3√2) = (3-2√2)

Step-by-step explanation:

(6-3√2)/(6+3√2)

To rationalize, we multiply (6-3√2) in both NUMERATOR and DENOMINATOR and solving it :-

=(6-3√2)²/(6+3√2)(6-3√2)

={6²+(3√2)²-2.6.3√2 }/6²-(3√2)²

=(36+18-36√2)/36-18

=(54 -36√2)/18

Taking 2 as common from both numerator and denominator and cancelling them:-

=(27-18√2)/9

Again taking 3 as common from both numerator and denominator and cancelling them:-

=(9-6√2)/3

Again taking 3 as common from both numerator and denominator and cancelling them:-

=(3-2√2)/1

The FINAL answer is:-

=(3-2√2)


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