Ramesh purchased a car at Rs x, he sold his car at 90% profit to Sures

1.	Ramesh purchased a car at Rs x, he sold his car at 90% profit to Suresh at Rs y, Suresh sold the car to Ganesh at a profit of 20%, if Ganesh purchased the car at Rs 1140000, then find the value of y – x in Rupees. 1. 3500002. 4000003. 4500004. 500000
Answer» Correct Answer - Option 3 : 450000 Given : Ramesh purchased the car at Rs x Ramesh sold the car to Suresh at 90% profit at a selling price of Rs y Suresh purchased the car at Rs y Suresh sold the car to Ganesh at a 20% profit. at Rs 1140000 Ganesh purchased the car at Rs 1140000 Formula used : Profit% = (selling price – cost price)/cost price) × 100 Calculations : Suresh sold the car Rs 1140000 at 20% profit 20 = (1140000 – y/y) × 100 (using the above-given formula, here y is the cost price and 1140000 is the selling price for Suresh) 20/100 = (1140000 – y)/y 1/5 = (1140000 – y)/y 6y = 5 × 1140000 ⇒ y = 950000 Similarly for Ramesh who sold the car at 15% profit at Rs y (y = 950000) 90 = (950000 – x)/x) × 100 (using above given formula, where x is the cost price and 950000 is the selling price for Ramesh) 90/100 = (950000 – x)/x 9/10 = (950000 – x)/x 19x = 950000 × 10 ⇒ x = 500000 Now y – x = 950000 – 500000 ⇒ 450000 ∴ The value of y – x is Rs 450000.

Ramesh purchased a car at Rs x, he sold his car at 90% profit to Suresh at Rs y, Suresh sold the car to Ganesh at a profit of 20%, if Ganesh purchased the car at Rs 1140000, then find the value of y – x in Rupees. 1. 3500002. 4000003. 4500004. 500000

Answer» Correct Answer - Option 3 : 450000

Given :

Ramesh purchased the car at Rs x

Ramesh sold the car to Suresh at 90% profit at a selling price of Rs y

Suresh purchased the car at Rs y

Suresh sold the car to Ganesh at a 20% profit. at Rs 1140000

Ganesh purchased the car at Rs 1140000

Formula used :

Profit% = (selling price – cost price)/cost price) × 100

Calculations :

Suresh sold the car Rs 1140000 at 20% profit

20 = (1140000 – y/y) × 100 (using the above-given formula, here y is the cost price and 1140000 is the selling price for Suresh)

20/100 = (1140000 – y)/y

1/5 = (1140000 – y)/y

6y = 5 × 1140000

⇒ y = 950000

Similarly for Ramesh who sold the car at 15% profit at Rs y (y = 950000)

90 = (950000 – x)/x) × 100 (using above given formula, where x is the cost price and 950000 is the selling price for Ramesh)

90/100 = (950000 – x)/x

9/10 = (950000 – x)/x

19x = 950000 × 10

⇒ x = 500000

Now

y – x = 950000 – 500000

⇒ 450000

∴ The value of y – x is Rs 450000.