Rakesh needs 1.71 g of sugar (CH..0..) to sweeten his tea. What would

1.	Rakesh needs 1.71 g of sugar (CH..0..) to sweeten his tea. What would be the number of carbon atom presentin his tea:(A) 3.6 10-(B) 7.2 * 1021(C) 0.05 102(D) 6.6 x 1022
Answer» ANSWER: The answer is (A) EXPLANATION: The number of moles is the RATIO of mass to MOLAR mass. Moles of Sugar = 3421.71=2001 mol The number of molecules is the product of the number of moles and Avogadro's number NA=6.023×1023. Number of molecules = 2001×NA Number of C ATOMS = 12×2001×NA =3.6 ×10 22

Rakesh needs 1.71 g of sugar (CH..0..) to sweeten his tea. What would be the number of carbon atom presentin his tea:(A) 3.6 10-(B) 7.2 * 1021(C) 0.05 102(D) 6.6 x 1022

Answer»

The answer is (A)

The number of moles is the RATIO of mass to MOLAR mass.

Moles of Sugar = 3421.71=2001 mol

The number of molecules is the product of the number of moles and Avogadro's number NA=6.023×1023.

Number of molecules = 2001×NA

Number of C ATOMS = 12×2001×NA

=3.6 ×10 22