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Raju opens a nut with the help of a spanner of length 20cm by applying a force of 100N. What should be the minimum length of the spanner if his younger brother Jai opens it with a force of 40N? ​

Answer» EXPLANATION:MOMENT of FORCE = f×dF=100n,d=20cm100×20=200nm200nm=40×dD=200/40=5cmHOPE IT HELPS YOU


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