Rain appears to fall vertically downward to a man moving with a veloci

1.	Rain appears to fall vertically downward to a man moving with a velocity of 4m/sec. When he doubles his speed then the rain appears to strike him at an angle of 45 degree with the horiozontal. Then what is the actual velocity of rain drop?I don't need any Google answers please do not copy and paste the answer
Answer» The speed of the RAINDROP is 4 √2 m/s and the angle is 45°. Explanation: Initial velocity of the man, me = 4 m/s Final velocity of the man, m'e = 8 m/s m'm = m'e - me = 8 - 4 = 4 m/s tan 45 = rm/m'm rm = (m'm) tan 45 = 1 re = √(rm)^2 + (me)^2 = 4 √2 m/s θ = tan^-1 (me / rm) = tan^-1 (1) θ = 45° degree Hence the speed of the raindrop is 4 √2 m/s and the angle is 45°. ALSO learn more Rain is falling vertically downwards with a velocity of 3 km/hr. a man WALKS in the rain with a velocity of 4 km/hr. the raindrops will FALL on the man with a velocity of? brainly.in/question/4750322

Rain appears to fall vertically downward to a man moving with a velocity of 4m/sec. When he doubles his speed then the rain appears to strike him at an angle of 45 degree with the horiozontal. Then what is the actual velocity of rain drop?I don't need any Google answers please do not copy and paste the answer

Answer»

The speed of the RAINDROP is 4 √2 m/s and the angle is 45°.

Explanation:

Initial velocity of the man, me = 4 m/s

Final velocity of the man, m'e = 8 m/s

m'm = m'e - me = 8 - 4 = 4 m/s

tan 45 = rm/m'm

rm = (m'm) tan 45 = 1

re = √(rm)^2 + (me)^2 = 4 √2 m/s

θ = tan^-1 (me / rm) = tan^-1 (1)

θ = 45° degree

Hence the speed of the raindrop is 4 √2 m/s and the angle is 45°.

ALSO learn more

Rain is falling vertically downwards with a velocity of 3 km/hr. a man WALKS in the rain with a velocity of 4 km/hr. the raindrops will FALL on the man with a velocity of?

brainly.in/question/4750322

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The speed of the RAINDROP is 4 √2 m/s and the angle is 45°.

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