Rahul, and Abhishek can do a piece of work in 10, and 20 days respecti

1.	Rahul, and Abhishek can do a piece of work in 10, and 20 days respectively, and they together earn Rs 1200. Find the share of Rahul.1. Rs 6002. Rs 8003. Rs 9004. Rs 400
Answer» Correct Answer - Option 2 : Rs 800 Given: Rahul can do a piece of work in 10 days. Abhishek can do a piece of work in 20 days. Total earning = Rs 1200 Concept: Wages are distributed in proportion to the work done and in inverse proportion to the time taken by the individual. Calculation: 1 day work of Rahul = 1/10 1 day work of Abhishek = 1/20 Ratio of their work = 1/10 ∶ 1/20 ---- (1) Take L.C.M. of 10, 20 and then multiply it with equation (1) ⇒ 20/10 ∶ 20/20 ⇒ 2 ∶ 1 Ratio of their wages = 2 ∶ 1 Let Rahul’s share is 2x, and Abhishek’s share is x. Rahul’s share + Abhishek’s share = 1200 ⇒ 2x + x = 1200 ⇒ 3x = 1200 ⇒ x = 400 Rahul’s share = 2x ⇒ 2 × 400 ⇒ 800 ∴ The share of Rahul is Rs 800.

Rahul, and Abhishek can do a piece of work in 10, and 20 days respectively, and they together earn Rs 1200. Find the share of Rahul.1. Rs 6002. Rs 8003. Rs 9004. Rs 400

Answer» Correct Answer - Option 2 : Rs 800

Given:

Rahul can do a piece of work in 10 days.

Abhishek can do a piece of work in 20 days.

Total earning = Rs 1200

Concept:

Wages are distributed in proportion to the work done and in inverse proportion to the time taken by the individual.

Calculation:

1 day work of Rahul = 1/10

1 day work of Abhishek = 1/20

Ratio of their work = 1/10 ∶ 1/20 ---- (1)

Take L.C.M. of 10, 20 and then multiply it with equation (1)

⇒ 20/10 ∶ 20/20

⇒ 2 ∶ 1

Ratio of their wages = 2 ∶ 1

Let Rahul’s share is 2x, and Abhishek’s share is x.

Rahul’s share + Abhishek’s share = 1200

⇒ 2x + x = 1200

⇒ 3x = 1200

⇒ x = 400

Rahul’s share = 2x

⇒ 2 × 400

⇒ 800

∴ The share of Rahul is Rs 800.

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