Radius of circle is 10 cm. There are two chords of length 16 cm each.

1.	Radius of circle is 10 cm. There are two chords of length 16 cm each. What witdistance of these cho1.rds from the centre of the circle t
Answer» Given :- Length of the chord AB = 16cm and radius ( r ) = 10cm . To find :- OM Construction :- Draw a perpendicularOM from centre O such that, it bisects the chord AB. Proof :- In right angled ∆OMB, OB^2 = OM^2 + BM^2 => 10^2 = OM^2 + 8^2 => 100 = OM^2 + 64 => OM^2 = 36 => OM = √36 => OM = 6 cm

Radius of circle is 10 cm. There are two chords of length 16 cm each. What witdistance of these cho1.rds from the centre of the circle t

Answer»

Given :- Length of the chord AB = 16cm and radius ( r ) = 10cm .

To find :- OM

Construction :- Draw a perpendicularOM from centre O such that, it bisects the chord AB.

Proof :- In right angled ∆OMB,

OB^2 = OM^2 + BM^2

=> 10^2 = OM^2 + 8^2

=> 100 = OM^2 + 64

=> OM^2 = 36

=> OM = √36

=> OM = 6 cm