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R17 If cosO+ sin0 = V2coso, show that cos 0 -sin 0 = 2 |
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Answer» cos o=/2 cos o-sinocoso-sino=/2coso_sino-sino =/2 It is correct answer cosx + sinx=V2 cosx, then ( V2-1) cosx= sinx, multiplying both sides by V2+1, we get ( V2+1)( V2-1)cosx=(V2+1)sinx =cosx=V2sinx+ sinx; cosx-sinx=V2sinx, (V2+1)(V2-1)cosx=(V2+1)sin5x ;we know that; (a+b)(a-b)=a^2-b^2; ( V2)^2-(1)^2 cosx= ( V2+1)sinx; 2-1cosx=(V2+1)sinx, cosx=(V2+1)sinx;; cosx = V2 sinx + sinx; cosx-sinx= V2 sinx; cosx-sinx=+- sinx it is correct answer it is correct answer |
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