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R1 = 100 ± 3 R2 = 200 ± 4 Find the resistance in series and parallel combination . My solution : Series connection RS =(100±3)+(200±4) Rs =300±7 Parallel connection Rp = (R1R2)÷(R1 + R2) Rp = {(3/100)(4/200)}÷(300±7) Rp = (3/5000)÷(300±7) What to do after this ??? I am not able to get it . Please help me out . |
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Answer» R1 = 100 ± 3 R2 = 200 ± 4 Find the resistance in series and parallel combination . My solution : Series connection RS =(100±3)+(200±4) Rs =300±7 Parallel connection Rp = (R1R2)÷(R1 + R2) Rp = {(3/100)(4/200)}÷(300±7) Rp = (3/5000)÷(300±7) What to do after this ??? I am not able to get it . Please help me out . |
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