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ŕ¤ŕĽ .es = 5T |
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Answer» let x= √6+√6+√6... Squaring both sides, we get x2=6+√6+√6+√6... x2=6+x x2-x-6=0 x2-3x+2x-6=0 x(x-3)+2(x-3)=0 (x-3)(x+2)=0 x=-2,3 As √6+√6+√6... is positive So, the value of √6+√6+√6... is3 |
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