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r cosθ + sinθν2sinf, show that siné-cost -./2 cose. |
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Answer» Consider theta as A cosA+sinA=√2cosAsquaring both the sides =>(cosA+sinA)^2=2cos^2A=>cos^2 A +sin^2 A+2sinAcosA=2cos^2 A=>cos^2 A-2cos^2 A+2sinAcosA= -sin^2 A=> -cos^2 A+2sinAcosA= -sin^2 A=> cos^2 A-2sinAcosA=sin^2 Aadding sin^2 A on both the sides => cos^2 A+sin^2 A-2sinAcosA=2sin^2 A=> (cosA-sinA)^2 =2sin^2 A use square root both side,=> cosA-sinA=√2sinA it's okay... but it's was to complement... I need more easy process to understand... but thanxxx for that |
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