QuestloR T7. If H.C.F. of 210 and 55 is expressible in the form 210 x5

1.	QuestloR T7. If H.C.F. of 210 and 55 is expressible in the form 210 x5 +55y, find the value of y
Answer» Let us first find the HCF of 210 and 55. Applying Euclid division lemna on 210 and 55, we get 210 = 55 × 3 + 45 55 = 45 × 1 + 10 45 = 4 × 10 + 5 10 = 5 × 2 + 0 We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55. ∴ 5 = 210 × 5 + 55y ⇒ 55y = 5 - 1050 = -1045 ∴y = -19

QuestloR T7. If H.C.F. of 210 and 55 is expressible in the form 210 x5 +55y, find the value of y

Answer»

Let us first find the HCF of 210 and 55.

Applying Euclid division lemna on 210 and 55, we get

210 = 55 × 3 + 45

55 = 45 × 1 + 10

45 = 4 × 10 + 5

10 = 5 × 2 + 0

We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.

∴ 5 = 210 × 5 + 55y

⇒ 55y = 5 - 1050 = -1045

∴y = -19