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Question1. Mr. A is the owner of a house property whose municipal valuation is # 75,000 and fair rent is 80,000 (Not covered by Rent Control Act). The construction of the property was commencedon 1st January, 2015 and completed on 30th April, 2016. The building comprises of three units and is let-out to Mr. X, Y and Z on an annual rent of 30,000 per unit. Mr. A paid municipaltax of 12,000 for the entire building during the previous year. Find out the annual value ofthe house if Mr. X and Y have taken their units for residential purposes and Mr. Z for hisbusiness purpose. |
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Answer» Answer: Width of rectangle is 25 cm. Step-by-step explanation: Given :- A WIRE BEND in form of square of side 30 cm. Then wire is again bend in form of rectangle of length 35 cm. To FIND :- Width of the rectangle. Solution :- Here, Concept is : If we are BENDING wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape. So, Perimeter of square = 4 × side ⟶ Perimeter = 4 × 30 ⟶ Perimeter = 120 Thus, Perimeter of square is 120 cm. According to concept, Perimeter of square and perimeter of rectangle are equal. So, Perimeter of rectangle is 120 cm. Let, Breadth or width or rectangle be x cm. We know, Perimeter of rectangle = 2(Length + Breadth) ⟶ 120 = 2×(35 + x) ⟶ 120 = 70 + 2x \⟶ 120 - 70 = 2x ⟶ 50 = 2x ⟶ 50/2 = x ⟶ x = 25 We take, Width of rectangle be x. Therefore, Width of rectangle is 25 cm. |
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