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Question: There are 3 events, E1, E2, and E3, one of which must and only can happen.The odds are 7 to 1 against E1, 5 to 3 against E2. Find the odds against E3. |
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Answer» Step-by-step EXPLANATION: the peobabilities in this case must ADD to 1. Therefore you can do 1 - 1/7 - 3/5 which is EQUAL to 9/35 Hope this helps |
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