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Question No.5 In Dumas method for estimation of nitrogen 0.30 gof an organic compound gave 50 ml of nitrogencollected at 300 K and 715 mm of Hg pressure.The percentage composition of nitrogen in thecompound is, if aqueous tension at 300 K is 15 mmof Hg. |
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Answer» 6.25 %Explanation:Here, Mass of organic substance =0.3 gVolume of Nitrogen collected =50 mLTemperature (T1)=300 KVapour pressure of water =15 mmActual pressure of dry nitrogen =715−15=700 mmAt STP, we know that P2=760 mm and T2 =273K then V2 =?====> P1 V1/ T1 = P2V2/ T2====>( 700 x 50) /309 = (700 x V2)/273====> V2 = 41.9 mlHence, % if Nitrogen = (28 x 41.9 x 100)/22400= 5.238 =6.25%(nearly)HOPE THIS HELPS YOU¶ THANK YOU ¶PLEASE MARK AS BRAINLIEST ™ ® |
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