Question is attached Find the equation of following attachment

1.	Question is attached Find the equation of following attachment
Answer» ANSWER : ${(x + 1)}^{2} + {(y - 7)}^{2} = 8$ EXPLANATION : The given circle has P(-3,5) and Q(1,9) as its diameter. The center can be OBTAINED USING the MIDPOINT rule. $( \frac{ - 3 + 1}{2} , \frac{5 + 9}{2} )$ $( - 1,7)$ The radius is obtained using the distance formula, $r = \sqrt{( - 1 - (- 3 ))^{2} + {(7 - 5)}^{2} }$ $r = \sqrt{( 2)^{2} + {(2)}^{2} } = \sqrt{8}$ The equation is given by ${(x - h)}^{2} + {(y - h)}^{2} = {r}^{2}$ We substitute the center and radius to get: ${(x - ( - 1))}^{2} + {(y - 7)}^{2} = { (\sqrt{8}) }^{2}$ ${(x + 1)}^{2} + {(y - 7)}^{2} = 8$

Answer»

ANSWER :

${(x + 1)}^{2} + {(y - 7)}^{2} = 8$