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Question: How Many F- Ions Are Present In 2.50 Moles Of BaF2? |
Answer» 2.50molBaF2 X 2molF-/1molBaF2 x 6.02x10^23F-/1molF- = 3.01 x 10^24If you satisfy on my answer PLEASE mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️✏️✏️✏️
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