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Question from class 9 mathematics. Please solve and I will mark you brainliest.

Answer»

ANSWER:

{(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab

a+b = 10

{a}^{2} + {b}^{2} = <klux>58</klux>

Putting the VALUE in the formula

100 = 58 + 2ab

100-58 = 2ab

42 = 2ab

\frac{42}{2} = ab

21 = ab.

{(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)

{a}^{3} + {b}^{3} = {(a + b)}^{3} - 3ab(a + b)

{(a + b)}^{3} = {10}^{3} - 3(21)(58)

=1000 - 3654

= -2654


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