Question : At a particular locus, frequency of allete A is 0.6 and that of allele a is 0.4. what would be the frequency of heterozygotes in a random mating population at equilibrium?

Question : At a particular locus, frequency of allete A is 0.6 and tha

1.	Question : At a particular locus, frequency of allete A is 0.6 and that of allele a is 0.4. what would be the frequency of heterozygotes in a random mating population at equilibrium?
Answer» 0.36 0.16 0.24 0.48 Solution :In a STABLE population, for a GENE with two alleles, 'A' (dominant) and 'a'(RECESSIVE), if the frequency of 'A'is P and the frequency of 'a' is q, then the frequencies of the three possible genotypes (AA,Aa and aa) can be expressed by the Hardy-Weinberg equation: `p^(2)+2pq+q^(2)=1` where `p^(2)=` FREQEUNCY of A A (HOMOZYGOUS dominant) Inviduals `q^(2)=` Frequency of Aa (heterozygous) individuals. so, p=0.6 and q=0.4 (given) `therefore 2pq` (frequency of heterozygote) `=2xx0.6xx0.4=0.48`.