Question: A constant horizontalforce of 250 N acts for adistance of 36

1.	Question: A constant horizontalforce of 250 N acts for adistance of 36 m on a 500 kgbox. If friction is neglected andthe box starts from rest, what isits velocity?
Answer» Explanation: Work F = ma 250= 500 × a a =0.5m/s^2 We KNOW that, v^2 = u^2 + 2as v^2 = 0 + 2 × 0.5 × 36 【initially body was at rest , u=0】【distance travelled = 36m, s= 36m】 v^2 = 36 v = +- 6 \|v\| = 6m/s MARK ME AS BRAILIEST F O L L O W ME

Question: A constant horizontalforce of 250 N acts for adistance of 36 m on a 500 kgbox. If friction is neglected andthe box starts from rest, what isits velocity?

Answer»

Explanation:

Work

F = ma

250= 500 × a

a =0.5m/s^2

We KNOW that,

v^2 = u^2 + 2as

v^2 = 0 + 2 × 0.5 × 36

【initially body was at rest , u=0】

【distance travelled = 36m, s= 36m】

v^2 = 36

v = +- 6

|v| = 6m/s

MARK ME AS BRAILIEST

F O L L O W ME

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Question: A constant horizontalforce of 250 N acts for adistance of 36 m on a 500 kgbox. If friction is neglected andthe box starts from rest, what isits velocity?​