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Question 8.7: The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?Class 12 - Physics - Electromagnetic Waves Electromagnetic Waves Page-286

Answer»

Amplitude of MAGNETIC field of an electromagnetic WAVE in a VACCUM ,
B_0=510nT
speed of LIGHT in vacuum,c = 3 × 10^8 m/s
amplitude of electric field of the electromagnetic wave is given by the relation,
E_0=cB_0=3\times10^8\times510\times10^{-9}\\E_0=153N/C

therefore electric field part of the wave is 153N/C



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