Saved Bookmarks
| 1. |
Question 7.8: Suppose the initial charge on the capacitor in Exercise 7.7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?Class 12 - Physics - Alternating Current Alternating Current Page-266 |
|
Answer» According to question 7.7, Capacitance ( C ) = 30 цf 1 цf = 10⁻⁶ f => 30 цf = 30 * 10⁻⁶ f Inductance ( L ) = 27 mH 1 mH = 10⁻³ H => 27 mH = 27 * 10⁻³ H Charge of the conductor ( Q ) = 6 mC 1 mC = 10⁻³ C => 6 mC = 6 * 10⁻³ C We know that, ENERGY = Q² / 2C => Energy = ( 6 * 10⁻³ )² / 2 * 30 * 10⁻⁶ => Energy = 36 * 10⁻⁶ C / 60 * 10⁻⁶ F => Energy = 36 / 60 = 6 / 1 0= 0.6 J Hence energy stored is 0.6 J. This energy will be same in LATER time also as it is shared between Inductor and capacitor. |
|