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Question 6.9: A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?Class 12 - Physics - Electromagnetic Induction Electromagnetic Induction Page-230

Answer»

Given,
Mutual conductance, μ = 1.5 H
Initial CURRENT i₁= 0
Final current i₂ = 20 A
Time taken t = 0.5 seconds
Change in the current can be CALCULATED as,DI = 20 – 0
dI = 20 A
The mutual conductance of the CIRCUIT is calculated using the formula,
e=\mu\frac{di}{dt}\\\mu=\frac{e}{\frac{di}{dt}}
As we know,e=\frac{d\phi}{dt}

\frac{d\phi}{dt}=\mu\frac{di}{dt}\\d\phi=\mu di
= 1.5 H × 20A
= 30Wb

Hence, the change in flux linkage is 30Wb


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