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Question 5.24: A Rowland ring of mean radius 15 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. What is the magnetic field B in the core for a magnetising current of 1.2 A?Class 12 - Physics - Magnetism And Matter Magnetism And Matter Page-203

Answer»

Number of turns , N = 3500
radius of Rowland ring , r= 15cm = 0.15 m
RELATIVE permeability, \mu_r=800
CURRENT, I = 1.2A

we know, MAGNETIC in the CORE is given by
B=\mu_mni=\frac{\mu_mNi}{2\pi r}
because relative permeability = permeability of medium/permeability of vacuum
\mu_r=\frac{\mu_m}{\mu_0}\\\mu_m=\mu_0\mu_r
so,B=\frac{\mu_0\mu_rNI}{2\pi r}
= 4π × 10^-7 × 800 × 3500 × 1.2/(2π × 0.15)
= 4.48T

hence, magnetic FIELD ,B = 4.48T


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